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Message no. 1
From: shadowrn@*********.com (Lars Wagner Hansen)
Subject: Metahumanity Question.(long)
Date: Fri Jan 25 11:30:01 2002
From: "Jane VR" <kadjari@*******.com>
> >Don't that depend on how the genes behave, which one is the dominant
> >one and some other scientific mumbo-jumbo?
> >
> >At least in SR the metagenes have a strong part, otherwise we would
> >have half breeds, so that should be stated as a fact.
>
> >You could also consider it this way:
> >
> >Each person have two metegenes, of which one of them is the strong
> >part, whioch will correspond with the persons race.
>
> >Normally you could giev each of your metagenes to each of your
> >children, and there by get the situation you described. But if you
> >could only give your strong metagene, then from a dwarf you
> >could only get the dwarf metagene, from a huna only the human
> >metagene etc. You would get the following situation:
>
> Lars, I'm interested in this discussion, but I don't understand what
> you're saying at all. Could you rephrase it maybe? What do you
> mean by 'strong part'? Why would you only pass on the strong
> gene?

OK I'll try again.

When it comes to eye colour, you have a pair of genes that determine your eye
colour. Some genes are stronger than otheres.

If we simpleyfy this, you can only have two colour genes, a blue or a brown. We
will say that the blue gene is the stronger of the genes.
A person with two blue genes, will have blue eyes.
A person with two brown genes will have brown eyes.
A person with a blue and a brown gene, will have blue eyes (half-blue).

When you produce a child, you will pass on one of your two genes.

A person with brown eyes will always pass on a brown gene, where as a person
with blue eyes will pass on a blue gene (if they are true blue eyed), or a blue
or a brown (50% chance of each, if they are half-blue eyed).

So two brown eyed people will always have brown eyed babies.

Two "true" blue eayed persons can also only have blue eyed babies (true blue
eyed).

Two half-blue eyed persons can have babies with both colours (and be both true,
half-blue and brown eyed).

A half-blue eyed person and a brown eyed person could have babies with both
colours (which will either be half-blue or brown eyed).

A "true" blue eyed person and a brown eyed person can only have blue eyed babies
(which will in fact be half-blue eyed)

Then again there are cases where this don't hold trye, as nature are fickle,
just look at David Bowie with two different couloured eyes.

So when it comes to metagenes we could apply the same technique.

Now when we are all human, both of your parents can only pass on a human
metagene, and your will therefore end up with two human metagene, and you will
yourself be a human. In reality this isn't true in SR, as the metagenes are
different, but just dosn't show their difference until 2011 and beyond.

In SR we all have two metagenes. I label the metagenes with letters that
correspond to the races: H=Human, E=Elf, D=Dwarf, O=Ork and T=Troll.

So for the true races, you will have the following metagene combinations:

HH = Human
EE = Elf
DD = Dwarf
OO = Ork
TT = Troll

When you create a child you could normally pass on any one of your two
metagenes. WE already know that there arne no half-breeds in SR, which will mean
that somebody with two different metagenes, will have a 50% of showing that
races characteristics. This leads us to the following combinations of metagenes,
and races:

HH = 100% Human
HE or EH = 50% Human, 50% Elf
HD or DH = 50% Human, 50% Dwarf
HO or OH = 50% Human, 50% Ork
HT or TH = 50% Human, 50% Troll
EE = 100% Elf
ED or DE = 50% Elf, 50% Dwarf
EO or OE = 50% Elf, 50 % Ork
ET or TE = 50% Elf, 50% Troll
DD = 100% Dwarf
DO or OD = 50% Dwarf, 50% Ork
DT or TD = 50% Dwarf, 50% Troll
OO = 100% Troll
OT or TO = 50% Ork, 50% Troll
TT = 100% Troll

So if you know somebody is a troll, dosn't mean that you know what both of his
metagenes are. He could be a TT, OT, TO, TD, DT, ET, TE, HT or TH. Furthermore
there will be 50% of him passing on the gene not showing. So a TE could pass on
his E metagene.

If a TT troll has a baby with another TT troll, the baby will always be a TT
troll.

If a TT troll has a baby with a TH troll, there is a 50% cahnca of the baby
being a TT troll, 25% chance of a TH troll, and 25% chance of a TH human.

So if a TE troll has a baby with a DT troll, they could in fact create the
following babies:
25% TT = 100% Troll
25% ET/ET = 50% Elf, 50% Troll
25% TD/DT = 50% Dwarf, 50% Troll
25% ED/DE = 50% Dwarf, 50% Elf

All in all there are 50% of the baby being a troll, 25% chance of the baby being
a dwarf and 25% chance of the baby being an elf. This i the reason why two
trolls could actually have three different babies (race wise). An to make
matters more interesting, the dwarf baby could actualy make its own elf baby (if
the dwarf was a ED dwarf).

So despite both of your parents being troll, you could yourself be a dwarf, and
have yourself an elf baby!

Just think of the psychological problems.

Thats why I thought up the idea of the strong metagene. At first I tried just
playin with the metagenes being of a different value, wher the one with the
highest value being the race showing.

So H would be 5, E=4, D=3, O=2 and T=1

So a HT would always look lie a human, since the H would be stronger than the T.
That lead to the following metagene combinations and races:
HH/HE/HD/HO/HT = Human
EE/ED/EO/ET = Elf
DD/DO/DT = Dwarf
OO/OT = Ork
TT = Troll

But this only lead to the fact that the proportion of the different races was
like, but not equal to, the distribution in the world. You still had the problem
with a HT human and a EO elf, could have the following babies:
HE human, HO human, ET elf or OT ork.

But what if there still was a 50% chance of one of the genes being the strong
one. A HT could be either a HT human, or a TH Troll.

Thats where I started using a different notation. In the following I use a
capital letter for the strong metagene, and lower-case leter for the weak
metagene.

So the different races could have the following metagene combinations:
Human: Hh, He, Hd, Ho, Ht
Elf: Eh, Ee, Eo, Et
Dwarf: Dh, De, Dd, Do, Dt
Ork: Oh, Oe, Od, Oo, Ot
Troll: Th, Te, Td, To, Tt

In addition you could only pass on yoru strong metagene, and in the baby there
would be 50% chance of either of the genes from the parents would become the new
strong metagene.

So a human, could only pass on the H metagene, even if it was a He/Hd/Ho/Ht
human.

A pair of trolls could only pass on the T metagene, and would therefore produce
a Tt troll.

A human and an elf would always pass on the H and E metagene, and could produce
a He human or an Eh elf.

Whoa that was long, but I hope it helps.

Lars
--
Lars Wagner Hansen, Jagtvej 11, 4180 Sorø
l-hansen@*****.tele.dk http://home4.inet.tele.dk/l-hansen
--
SRGC v0.22 SR1 SR2++ SR3+++ h+ b+++ B--- UB++ IE+ RN LST W++ dk sa++ ma+
sh++ ad++++ ri mc rk-- m- (e-- o t-- d-) gm+ M- P-
--
Main Rule of Usenet: Never argue with idiots. They drag you down to
their level, then beat you with experience.
Message no. 2
From: shadowrn@*********.com (Scott Harrison)
Subject: Metahumanity Question.(long)
Date: Fri Jan 25 12:45:01 2002
On Friday, January 25, 2002, at 05:37 , Lars Wagner Hansen wrote:
>
> Thats where I started using a different notation. In the following I
> use a
> capital letter for the strong metagene, and lower-case leter for the
> weak
> metagene.
>
> So the different races could have the following metagene combinations:
> Human: Hh, He, Hd, Ho, Ht
> Elf: Eh, Ee, Eo, Et
> Dwarf: Dh, De, Dd, Do, Dt
> Ork: Oh, Oe, Od, Oo, Ot
> Troll: Th, Te, Td, To, Tt
>
> In addition you could only pass on yoru strong metagene, and in the
> baby there
> would be 50% chance of either of the genes from the parents would
> become the new
> strong metagene.
>
> So a human, could only pass on the H metagene, even if it was a
> He/Hd/Ho/Ht
> human.
>
> A pair of trolls could only pass on the T metagene, and would therefore
> produce
> a Tt troll.
>
> A human and an elf would always pass on the H and E metagene, and could
> produce
> a He human or an Eh elf.
>
> Whoa that was long, but I hope it helps.
>
> Lars
>
Or you could say that when metagenes from two races mix, they will do
battle, and one will win out thereby suppressing and converting the
loser to the winner's type. This would make it so there is no troll
with a little bit of elf in him, but his elf gene would have become a
troll gene. This would explain how there is no possibility of 1/2
anythings. And you can always make up the chances that any races gene
would win a fight against another. E.g., an elf and troll mate and the
results are 75% and 25% troll because when the elf gene combats the
troll gene it wins 75% of the time.

--Scott
Message no. 3
From: shadowrn@*********.com (Jane VR)
Subject: Metahumanity Question.(long)
Date: Fri Jan 25 17:50:01 2002
>From: "Lars Wagner Hansen" <l-hansen@*****.tele.dk>

<snip>
>
>Whoa that was long, but I hope it helps.
>
>Lars
>--

Thanks, I get it now. We're all clutching at straws to justify the rulebook
again ;)

Jane


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