From: | David Buehrer <dbuehrer@******.CARL.ORG> |
---|---|
Subject: | Re: Open-ended Tests |
Date: | Fri, 31 Oct 1997 07:32:18 -0700 |
|
| David Buehrer said on 9:12/30 Oct 97...
|
| > Wouldn't it be easier to have both sides roll vs a base TN of 4? The
| > sneaker roles his stealth vs a 4. The perciever rolls his
| > intelligence vs a 4 modified by vision, the sneaker's movement
| > (reverse the walking/running modifiers) and concealment modifiers.
| > Whoever gets the most successes "wins".
|
| That's more or less the standard SR rule, and I don't think either is
| easier than the other.
The standard SR rule is that the sneaker's base TN is the perceiver's
intelligence and the perceiver's base TN is the sneaker's stealth.
[snip: misinterpretation]
| What I use as a house rule is to roll the STealth dice
| utnil there are no more sixes, and note the highest roll. Then that's the
| base TN for the Perception test. I'm not great at statistics so I don't
| know how the relation between number of Stealth dice and number of
| Perception dice affects the probabilities here, but it seems well
| enough balanced to me.
It would seem that luck would play a much greater role with this.
For example Sam (who's sneaking up on Fred) rolls his stealth, which
is one die, and ends up with a 15 (6+6+3). Fred has an intelligence
of 6, but he odds of him spotting Sam are practically nill (about
5%). That's not right, IMO.
-David
http://www.geocities.com/TimesSquare/1068/homepage.htm
--
"Creativity is allowing yourself to make mistakes. Art is knowing
which ones to keep."