From:	Robert Watkins robert.watkins@******.com
Subject:	Technological Teleportation/Energy Sources
Date:	Thu, 18 Mar 1999 09:27:19 +1000

> Ignoring all of the physical impossibilities of this
> teleportation method, let
> the engineers solve them ;-), and getting back to the original
> method- after
> the target is (destructively) scanned, why send the energy to the
> receiver?
> After all, a joule is a joule is a joule. Just reconstruct the
> target from a
> local energy / matter source. It's still the same target in every physical
> meaning, although the philosophers and priests would have a field
> day on this
> topic.

Because of the amount of energy involved. Conversion of energy to matter
uses the famous E=Mc^2 function. C is on the order of 3x10^8 m/s I think
(it's been a while...), so to reconstruct an 80kg person, you need...
80x(3x10^8)^2, or 80x9x10^16 joules.

As the Bookworm pointed out, it's roughly equivalent to a Megaton warhead
for each gram of the person. If you can generate the equivalent of 80000
Megatons of explosive, feel free.

In practise (gee, I'm talking about practicalities involved in a method I
said upfront was implausible...), you'd use a counterweight. Scan, send the
data, "convert" the two objects, and then recreate with the energy provided
by conversion. You don't really need to convert the counterweight back, but
lets not get into that... besides, you'd run out of counterweights
otherwise.

--
.sig deleted to conserve electrons. robert.watkins@******.com